Any Seven: The Worst Standard Bet on a Craps Table (16.67%)

Every craps layout has a spot the dealers themselves call a sucker bet. On most tables it’s “Any Seven”, sometimes announced as “Big Red”, a one-roll bet that the next roll is a seven. It carries the highest house edge of any standard bet on the table: 16.67%.

The exact math

Two dice make 36 combinations; six of them total seven (1-6, 2-5, 3-4, 4-3, 5-2, 6-1). So the next roll is a seven exactly 6/36 = 1 in 6, fair odds of 5 to 1.

The table pays 4 to 1.

EV = (1/6)(+4) + (5/6)(−1) = −1/6 = −16.67%.

You lose a full sixth of every dollar bet, per roll. For scale: that single bet costs more than eleven pass-line bets’ worth of edge, every time you toss a chip on it.

The irony

Seven is the most likely roll in craps; the whole game’s structure bends around that fact. Betting on the most common outcome and still getting robbed takes a specially engineered payout, and 4:1-on-a-5:1-shot is exactly that engineering. Frequency isn’t value; price is value.

Why it survives

Any Seven is sold as a hedge: “protect” your pass bet during the point, since a seven-out kills it. But paying 16.67% to insure a 1.41% bet is like buying a $200 warranty on a $20 toaster; the hedge costs more than the risk. Hedging low-edge bets with high-edge bets always loses money on net; the math has no exceptions.

The alternative

If you want action on sevens, the honest version already exists: the don’t pass line effectively roots for the seven at a 1.36% edge, twelve times cheaper than Big Red. And the free odds bet remains the only 0% wager in the house.

Watch Any Seven drain a stack in fast-forward; the simulator will run the experiment as many times as you can stand.